20x^-4/27y^2/8x^-3/15y^-5

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Solution for 20x^-4/27y^2/8x^-3/15y^-5 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

((x^-3*((((20*x^-4)/27)*y^2)/8))/15)*y^-5 = 0

1/162*x^-7*y^-3 = 0 // : 1/162*y^-3

x^-7 = 0

x należy do O

x belongs to the empty set

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